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30 August 2017

12 December 2010

  • curprev 23:5223:52, 12 December 2010Mwinlaw talk contribs 3,086 bytes +3,086 Created page with "To prove <math>\lambda_{\max}(\sum_{j \in I_k \cup \{i\}} a_ja_j^T) \geq \lambda_{\max}(\sum_{j \in I_k} a_ja_j^T) + (x_k^Ta_i)^2</math> we begin by finding the subgradient of th..."